Question

1) Calculate the enthalpy change for the reaction:

P4O6(s)+2O2(g)>>P4O10(s)
given the following enthalpies of reaction:
P4(s)+3O2(g)>>P4O6(s) deltaH = -1640.1 kJ
P4(s)+5O2(g)>>P4O10(s) deltaH = -2940.1 kJ

2) From the enthalpies of reaction:
H2(g)+F2(g)>>2HF(g) deltaH = -537kJ
C(s)+2F2(g)>>CF4(g) deltaH = -680kJ
2C(s)+2H2(g)>>C2H4(g) deltaH = +52.3kJ
calculate the deltaH for the reaction of ethylene with F2:
C2H4(g)+6F2(g)>>2CF4(g)+4HF(g)

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